Решите системы уравнений

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Решите системы уравнений


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Алгебра (947 баллов) | 47 просмотров
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Правильный ответ
\left \{ {{2*4^x+3*5^y=11} \atop {5*4^x+4*5^y=24}} \right. ;
 \left \{ {{-10*4^x-15*5^y=-55} \atop {10*4^x+8*5^y=48}} \right. ;
 \left \{ {{2*4^x+3*5^y=11} \atop {-7*5^y=-7}} \right. ;
 \left \{ {{2*4^x+3*1=11} \atop {5^y=1}} \right. ;\\\\
 \left \{ {{2*4^x=8} \atop {y=0}} \right. ;
 \left \{ {{4^x=4} \atop {y=0}} \right. ; \left \{ {{x=1} \atop {y=0}} \right. .
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\left \{ {{2^x-2^y=1} \atop {2^{3x}-2^{3y}=7}} \right. ;
 \left \{ {{2^x-2^y=1} \atop {(2^{x}-2^{y})(2^{2x}+2^x*2^y+2^{2y})=7}} \right. ;
 \left \{ {{2^x-2^y=1} \atop {2^{2x}+2^x*2^y+2^{2y}=7}} \right. ;\\\\
 \left \{ {{2^x-2^y=1} \atop {2^{2x}-2*2^x*2^y+2^{2y}+3*2^x*2^y=7}} \right. ;
 \left \{ {{2^x-2^y=1} \atop {(2^{x}-2^{y})^2+3*2^x*2^y=7}} \right. ;
 \left \{ {{2^x-2^y=1} \atop {1^2+3*2^x*2^y=7}} \right. ;\\\\
 \left \{ {{2^x-2^y=1} \atop {3*2^x*2^y=6}} \right. ;

\left \{ {{2^x-2^y=1} \atop {2^{x+y}=2^1}} \right. ;
 \left \{ {{2^x-2^y=1} \atop {x+y=1}} \right. ;
 \left \{ {{2^x-2^{1-x}=1} \atop {y=1-x}} \right. ;
 \left \{ {{2^x-\frac{2}{2^x}=1} \atop {y=1-x}} \right. ;
 \left \{ {{1*(2^x)^2-1*2^x-2=0} \atop {y=1-x}} \right. ;\\\\
 \left \{ {{2^x*2^x+1*2^x-2*2^x-2=0} \atop {y=1-x}} \right. ;
 \left \{ {{2^x*(2^x+1)-2(2^x+1)=0} \atop {y=1-x}} \right. ;
 \left \{ {{(2^x-2)*(2^x+1)=0} \atop {y=1-x}} \right. ;

\left \{ {{2^x-2=0} \atop {y=1-x}} \right. ;
 \left \{ {{2^x=2^1} \atop {y=1-x}} \right. ;
 \left \{ {{x=1} \atop {y=0}} \right. .
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