Помогите решить логарифмы под номерами 17 и 18 пожалуйста )

17)
$log_{0.2} (4x-1)\ \textless \ log_{0.2} (x+1)$
ОДЗ:
$\left \{ {{4x-1\ \textgreater \ 0} \atop {x+1\ \textgreater \ 0}} \right. ; \left \{ {{4x\ \textgreater \ 1} \atop {x\ \textgreater \ -1}} \right. ;\left \{ {{x\ \textgreater \ 0.25} \atop {x\ \textgreater \ -1}} \right. ; x\ \textgreater \ 0.25$
$4x-1\ \textgreater \ x+1$
$3x\ \textgreater \ 2$
$x\ \textgreater \ \frac{2}{3}$
Ответ: (2/3;+∞)

18)
$log_{0.5}(log_6 (x^2-3))\ \textgreater \ 0$
ОДЗ:
$\left \{ {{log_6 (x^2-3)\ \textgreater \ 0} \atop {(x^2-3)\ \textgreater \ 0}} \right. ; \left \{ {{x^2-3\ \textgreater \ 1} \atop {x^2-3\ \textgreater \ 0}} \right. ;\left \{ {{x^2\ \textgreater \ 4} \atop {x^2\ \textgreater \ 3}} \right. ; \left \{ {{x\ \textless \ -2} \atop {x\ \textgreater \ 2}} \right.$

$log_6 (x^2-3)\ \textless \ 1$
$log_6 (x^2-3)\ \textless \ log_6 6$
$x^2-3\ \textless \ 6$
$x^2\ \textless \ 9$
$-3\ \textless \ x\ \textless \ 3$
C учетом ОДЗ: (-3;-2)∪(2;3)