1) ( -√3/2)+ arccos (1/2)=? 2) 2sinx＝-√3 3) 1+sin^2x+cosx＝0 4)6sin^2x-3sinxcosx-cos^2x＝1

Question

1) ( -√3/2)+ arccos (1/2)=?
2) 2sinx＝-√3
3) 1+sin^2x+cosx＝0
4)6sin^2x-3sinxcosx-cos^2x＝1

Answer 1

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