0.5(2y-1)-(0.5-0.2y)+1=0

Question

0.5(2y-1)-(0.5-0.2y)+1=0

Answer 1

0.5(2у-1)-(0.5-0.2у)+1=0
1у-0.5-0.5+0.2у+1=0
1.2у=0+0.5+0.5-1
1.2у=0
у=0:1.2
у=0