log2x+log4x+log16x=14 ребят помогите срочно

Question

log2x+log4x+log16x=14 ребят помогите срочно

Answer 1

log2x+log4x+log16x=14 
log2(x)+log2(x)/log2(4)+log2(x)/log2(16)=14 
log2(x) (1+ 1/2+ 1/4)=14 
log2(x) 7/4 =14 
log2(x) =14 *4/7= 8 = log2(2^8)
x = 2^8   (или х =256)