Логорифмы, помогите), 179 задание

Решите задачу:

$log _{2}log _{2} log _{3}81=log _{2}log _{2}4=log _{2}2 =1\\\\log _{2}log _{3}log _{ \frac{1}{3}} \frac{1}{27}=log _{2}log _{3} 3=log _{2}1=0\\\\log _{ \sqrt{3} }log _{5} 125=log _{ \sqrt{3} }3 =2\\\\log _{4}log _{3}81=log _{4}4=1\\\\ \frac{1}{log _{9}27 } =log _{27}9=2log _{27}3=2* \frac{1}{3} = \frac{2}{3}\\\\ \frac{1}{log _{16}8 }=log _{8} 16 =4log _{16}2=4* \frac{1}{4} =1$