Помогите решить (4-2/5)÷(2ц3/4-1/6)×(1ц3/5+2ц1/4+3ц1/2)=

1) $\frac{5}{5} - \frac{2}{5} = \frac{3}{5}$

2) $\frac{11}{4} - \frac{1}{6} = \frac{33-3}{12} = \frac{30}{12} = \frac{5}{2}$

3) $\frac{3}{5} : \frac{5}{2} = \frac{3}{5} * \frac{2}{5} = \frac{6}{25}$

4) $\frac{8}{5} + \frac{9}{4} + \frac{7}{2} = \frac{24+45+70}{20} = \frac{139}{20}$

5) $\frac{6}{25} * \frac{139}{20} = \frac{139*3}{25*10} = \frac{417}{250} =1 \frac{167}{250}$