Пожалуйста,решите!!!!!!!!!!!!!!!!!

Решите задачу:

$12 \frac{5}{13} +y-9 \frac{9}{13} = \frac{98}{13}$
$\frac{161}{13} +y-9 \frac{9}{13} = \frac{98}{13}$
$\frac{161}{13} +y- \frac{126}{13}= \frac{98}{13}$
$y+ \frac{161-1*126}{13} = \frac{98}{13}$
$y+ \frac{161-126}{13} = \frac{98}{13}$
$y+ \frac{35}{13} = \frac{98}{13}$
$y=- \frac{35}{13} + \frac{98}{13}$
$y= \frac{63}{13}$