2sin(п+x)=sin2x-3sin^3 x
-2Sinx = Sin2x-3Sin^3 x
-2Sinx - 2SinxCosx + 3Sin^3 x= 0
Sinx(-2 -2Cosx + 3Sin² x) = 0
Sinx = 0 или 3Sin²x - 2Cosx -2 = 0
x = πn , n ∈ Z 3(1 - Cos²x) -2Cosx -2 = 0
3 - 3Cos²x -2Cosx -2 = 0
3Cos²x +2Cosx -1 = 0
Cosx = (-1 +-√4)/3 = (-1 +-2)/3
Cosx = -1, Cosx = 1/3
х = π+ 2πk , k ∈Z x = +-arcCos (1/3) +2πm,
m∈Z