Помогите решить (3х+5)(4х-1)=(6х-3)(2х+7)
12х^2 - 3х + 20 х - 5 = 12х^2 + 42х - 6х -21 12^2 - 3х + 20х - 5 - 12х^2 - 42х + 6х + 21 = 0 -19х + 16 = 0 -19х = -16 х = -16 : -19 х =
12x²-3x+20x-5=12x²+42x-6x-21 17x-5=36x-21 17x-36x=-21+5 -19x=-16 x=16/19