а)1+ cos 4x = cos 2x
2cos²2x=cos2x
2cos²2x-cos2x=0
cos2x(2cos2x-1)=0
cos2x=0
2x=π/2+πk
x=π/4+πk/2,k∈z
2cos2x-1=0
cos2x=1/2
2x=-π/3+2πk U 2x=π/3+2πk
x=-π/6+πk U x=π/6+πk,k∈z
Ответ x={π/4+πk/2;-π/6+πk;π/6+πk,k∈z}
б)4sin^2 x - 4sin x + 1 = 0
(2sinx-1)²=0
2sinx-1=0
sinx=1/2
x=(-1)^k*π/6+πk,k∈z