Решите уравнение а)2(2х-1)-3(х-2)=6+4(3-2х) б)2(х+2)-3(х-2)=5-4(3х-1)
А) 2(2x-1) - 3(x-2) = 6+4(3-2x) 4x - 2 - 3x + 6 = 6 + 12 - 8x 4x - 3x + 8x = 6 + 12 + 2 - 6 9x = 14 x = 14/9 б) 2(x+2) - 3(x-2) = 5-4(3x - 1) 2x + 4 - 3x + 6 = 5 - 12x + 4 2x - 3x + 12x = 4 - 4 - 6 + 5 11x = - 1 x = -1/11