How many liters of nitrogen will be produced from the splitting of 16 grams of ammonium...

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How many liters of nitrogen will be produced from the splitting of 16 grams of ammonium nitrite?

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Have:
m(NH₄NO₂) - 16 g.
To find: V(N₂) 
Solve:
16 g            V
NH₄NO₂ → N₂ + 2H₂O
64 g/mol    22,4 l/mol
V = \frac{16*22,4}{64} = 5,6 l
Answer: V(N₂) = 5,6 liters
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