F(x)= ln( 1-x)/x^2-2

Question

F(x)= ln( 1-x)/x^2-2

Answer 1

F'(x)=f(x) =  1/(1-x) * (-1) *(x²-2)  - ln(1-x) *2x / (x²-2) =

= -x²+2-2x ln(1-x)/(1-x)(x²-2)