F(x)=корень x *ln( 9-x^2)

Question

F(x)=корень x *ln( 9-x^2)

Answer 1

F'(x)=f(x)=1/2√x *ln(9-x²) + √x* 1/9-x² * (-2x)=

= ln(9-x²)/2√x -2x√x / (9-x)²