6×Sin60° (ctg 45° cos 30° + 1/2 ctg 30° ) решите пж!!!

Question

6×Sin60° (ctg 45° cos 30° + 1/2 ctg 30° )
решите пж!!!

Answer 1

6•sin60°(ctg45°•cos30°+1/2ctg30°)=
6•√3/2(1•√3/2+1/2•√3)
3√3(√3/2+√3/2)=3√3•2√3/2=3•√3•√3=
3•3=9

Comments

спс!