Sin4x-sinx=0 Найти кони на промежутке
2sin(3x/2)cos(5x/2)=0 sin(3x/2)=0 3x/2=πk x=2πk/3,k∈z π≤2πk/3≤5π/2 6≤4k≤15 6/4≤k≤15/4 k=2 x=4π/3 k=3 x=2π cos(5x/2)=0 5x/2=π/2+πk x=π/5+2πk/5 π≤π/5+2πk/5≤5π/2 10≤2+4k≤25 8≤4k≤23 2≤k≤23/4 k=2 x=π k=3 x=7π/5 k=4 x=9π/5 k=5 x=11π/5