Нужно подробное решение 795 номера

$\displaystyle log_{0,5}^{2}4x+log_{2}\frac{x^{2}}{8}=8\\\\odz:x\ \textgreater \ 0\\\\log_{2^{-1}}^{2}4x+log_{2}x^{2}-log_{2}8=8\\\\(-log_{2}4x)(-log_{2}4x)+2log_{2}x=11\\\\(log_{2}4+log_{2}x)*(log_{2}4+log_{2}x)+2log_{2}x=11\\\\(2+log_{2}x)*(2+log_{2}x)+2log_{2}x=11\\\\4+4log_{2}x+log_{2}^{2}x+2log_{2}x=11\\\\log_{2}^{2}x+6log_{2}x-7=0\\\\\\log_{2}x=y\\\\y^{2}+6y-7=0\\\\D=b^{2}-4ac=36+28=64\\\\y_{1,2}=\frac{-bб \sqrt{D}}{2a}\\\\y_{1}=1\\y_{2}=-7\\\\\\log_{2}x=1\\x_{1}=2\\\\ log_{2}x=-7\\x_{2}=\frac{1}{128}$

Ответ: {2; 1/128}