Найдите множество решений системы неравенств "система":√x^2-7>3; |2-3x|≤13

$\left \{ {{x^2-7\ \textgreater \ 9} \atop {-13 \leq 2-3x \leq 13}} \right. \\ \left \{ {{x^2\ \textgreater \ 16} \atop {-15 \leq -3x \leq 11}} \right. \\ \left \{ {{ \left [ {{x\ \textgreater \ 4} \atop {x\ \textless \ -4}} \right. } \atop {- \frac{11}{3} \leq x \leq 5}} \right.$

Ответ: $x\in (4; 5]$