Решите несложнорешить систему уравнений

Решите задачу:

$\left \{ {{x-y=3} \atop {x^2+y^2=29}} \right. \; \left \{ {(x-y)^2=9} \atop {x^2+y^2=29}} \right. \; \left \{ {{x^2+y^2-2xy=9} \atop {x^2+y^2=29}} \right. \; \left \{ {{29-2xy=9} \atop {x^2+y^2=29}} \right. \\\\ \left \{ {{2xy=20} \atop {x^2+y^2=29}} \right. \; \left \{ {{xy=10} \atop {x-y=3}} \right. \; \left \{ {{x(x-3)=10} \atop {y=x-3}} \right. \; \left \{ {{x^2-3x-10=0} \atop {y=x-3}} \right. \\\\ \left \{ {{x_1=-2\; ,\; x_2=5} \atop {y_1=-5\; ,\; y_2=2}} \right. \\\\Otvet:\; \; (-2,-5)\; ,\; (5,2)\; .$