2a+3ab-5b+a^2-b^2 +ab-4a^2+2ab-3b^2=

Question

2a+3ab-5b+a^2-b^2 +ab-4a^2+2ab-3b^2=

Answer 1

2а+6аb—5b+3a^2—2b^2=(2a+3a^2)—(5b–2b^2)+6ab=a ( 2+3a)–b(5—2b)+6ab=(2+3a)-(5–2b)+(6ab+ab) = 7+3a—2b+7ab