1) 54 = 2 · 3 · 3 · 3
1200 = 2⁴ · 3 · 5²
1200 | 2
600 | 2
300 | 2
150 | 2
75 | 5
15 | 5
3 | 3
1 |
1620 = 2² · 3⁴ · 5
1620 | 2
810 | 2
405 | 5
81 | 3
27 | 3
9 | 3
3 | 3
1 |
68 = 2² · 17
2) НОД(476, 855) = 1, значит, числа 476 и 855 взаимно простые
476 | 2 855| 5
238 | 2 171 | 3
119 | 7 57 | 3
17 | 17 19 | 19
1 | 1 |
3) НОД(144,30) = 2 · 3 = 6
144 | 2 30 | 2
72 | 2 15 | 3
36 | 2 5 | 5
18 | 2 1 |
9 | 3
3 | 3
1 |
НОД(128, 192) = 2⁶ = 64
128 | 2 192 | 2
64 | 2 96 | 2
32 | 2 48 | 2
16 | 2 24 | 2
8 | 2 12 | 2
4 | 2 6 | 2
2 | 2 3 | 3
1 | 1 |
4) 736200 : 18 - 640096 : 32 - 948 = 40900 - 20003 - 948 = 20897 - 948 = 19949