0 \\ 3x > 1 \\ x > \frac{1}{3} \\ \\ 3 - 2x > 0 \\ - 2x > - 3 \\ x < 1 \frac{1}{2} \\ ( \frac{1}{3} ; 1\frac{1}{2} )" alt=" log_{2}(3x - 1) \geqslant log_{2}(3 - 2x) \\ ОДЗ: \\ 3x - 1 > 0 \\ 3x > 1 \\ x > \frac{1}{3} \\ \\ 3 - 2x > 0 \\ - 2x > - 3 \\ x < 1 \frac{1}{2} \\ ( \frac{1}{3} ; 1\frac{1}{2} )" align="absmiddle" class="latex-formula">
Ответ: