Ребят, плиииииииззз пожалуйста помогите, и если можно то с фотографией!!!

Решите задачу:

$4 {x}^{2} = 16x \\ 4 {x}^{2} - 16x =0 \\ d = 256 - 4 \times 4 \times 0 = 256 \\ x1 = \frac{16 + 16}{2 \times 4} = \frac{32}{8} = 4 \\ x2 = \frac{16 - 16}{2 \times 4} = \frac{0}{8} = 0$

$5 {x}^{2} + 14x - 3 = 0 \\ d = 196 - 4 \times 5 \times ( - 3) = 196 + 60 = 256 \\ x1 = \frac{ - 14 + 16}{2 \times 5} = \frac{2}{10} = \frac{1}{5 } \\ x2 = \frac{ - 14 - 16}{2 \times 5} = \frac{ - 30}{10} = - 3 \\$
$36 {x}^{2} - 25 = 0 \\ d = 0 - 4 \times 36 \times ( - 25) = 0 + 3600 = 3600 \\ x1 = \frac{0 + 60}{2 \times 36} = \frac{60}{72} = \frac{5}{6} \\ x2 = \frac{0 - 60}{2 \times 36} = \frac{ - 60}{72} = \frac{ - 5}{6}$