Пример 5класс (6 1/4-4 1/8)*4+3 1/3:2 1/2

Решите задачу:

$(6 \frac{1}{4} - 4 \frac{1}{8} ) \times 4 + 3 \frac{1}{3} \div 2 \frac{1}{2} = ( \frac{25}{4} - \frac{33}{8} ) \times 4 + \frac{10}{3} \div \frac{5}{2} = \frac{59}{6}$

$1) \: \frac{25}{4} - \frac{33}{8} = \frac{25 \times 2}{4 \times 2} - \frac{33}{8} = \frac{50}{8} - \frac{33}{8} = \frac{17}{8}$

$2) \: \frac{17}{8} \times 4 = \frac{17 \times 4}{8} = \frac{17 \times 1}{2} = \frac{17}{2}$

$3) \: \frac{10}{3} \div \frac{5}{2} = \frac{10}{3} \times \frac{2}{5} = \frac{10 \times 2}{3 \times 5} = \frac{2 \times 2}{3 \times 1} = \frac{4}{3}$

$4) \: \frac{17}{2} + \frac{4}{3} = \frac{17 \times 3}{2 \times 3} + \frac{4 \times 2}{3 \times 2} = \frac{51}{6} + \frac{8}{6} = \frac{59}{6} .$

$otvet : \frac{59}{6}$