1) y= x^4 ; f’(x)=(x^4)’=4x^4-1=4x^3; 2)y=x^1/2 ; f’(x)=(x^1/2)’ = 1/2x^1/2-2/2=1/2x^-1/2; 3)y=x^-3; f’(x)=(x^-3)’=-3x^-3-1= -3x^-4; 4) y=3^(x^2); f’(x)=(x^2/3)’= 2/3x^2/3-3/3=2/3x^-1/3= 2/3(3^(x)); 5)y=1/x^3; f’(x) = (1/x^3)’= (x^-3)’=-3x^-4=-3/x^4;