(6+y)²-9²=0 100-(z-19)²=0

Question

(6+y)²-9²=0
100-(z-19)²=0

Answer 1

(6 + y)^2 - 9^2 = 0
(6 + y)^2 - 81 = 0
(6 + y)^2 = 81
6 + y = ±9
6 + y = 9
6 + y = -9
y2 = 3
y1 = -15

100 - (z - 19)^2 = 0
-(z - 19)^2 = -100
(z - 19)^2 = 100
z - 19 = ±10
z - 19 = 10
z - 19 = -10
z1 = 9
z2 = 29

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