Решить уравнение x²-4/4x=3x-2/2x

${x}^{2} - \frac{4}{4x} = 3x - \frac{2}{2x} \\ \frac{4x {}^{3} - 4 }{4x} = \frac{6x {}^{2} - 2 }{2x} \\ \frac{4x {}^{3} - 4}{4x} = \frac{12x {}^{2} - 4 }{4x} \\ 4x {}^{3} - 4 = 12x { }^{2} - 4 \\ 4 {x}^{3} - 4 - 12x {}^{2} + 4 = 0 \\4 {x}^{3} - 12x {}^{2} = 0 \\ x {}^{2} (4x - 12) = 0 \\ x {}^{2} = 0 \\ x = 0 \\ 4x - 12 = 0 \\ x - 3 = 0 \\ x = 3$
Ответ: x=0, x=3