Найдите корни уравнений: Номер 5.20.

Решите задачу:

$16x(2 - x) + (4x - 5)^{2} = 0 \\ 32x - 16 {x}^{2} + 16 {x}^{2} - 40x + 25 = 0 \\ 32x - 40x = - 25 \\ - 8x = - 25 \\ x = \frac{25}{8} \\ x = 3 \frac{1}{8} \\ \\$
$9y(y + 6) - (3y + 1)^{2} = 1 \\ 9 {y}^{2} + 54y - (9 {y}^{2} + 6y + 1) = 1 \\ 9 {y}^{2} + 54y - 9 {y}^{2} - 6y - 1 = 1 \\ 54y - 6y = 2 \\ 48y = 2 \\ y = \frac{2}{48} \\ y = \frac{1}{24}$