Помогите пожалуйста !!!

Решите задачу:

$((1\frac{1}{4})^2-\frac{5}{8})*10\frac{2}{3}-7\frac{1}{3}=((\frac{5}{4})^2-\frac{5}{8})*\frac{32}{3}-7\frac{1}{3}= \\ =(\frac{25}{16}-\frac{5}{8})*\frac{32}{3}-7\frac{1}{3}=(\frac{25}{16}-\frac{10}{16})*\frac{32}{3}-7\frac{1}{3}= \\ =\frac{15}{16}*\frac{32}{3}-7\frac{1}{3}=5*2-7\frac{1}{3}=10-7\frac{1}{3}=9\frac{3}{3}-7\frac{1}{3}=2\frac{2}{3}$