Помогите плз!! Там еще 3 1/2 + (2 3/4+1 1/2) =____

Question 1

Помогите плз!!
Там еще 3 1/2 + (2 3/4+1 1/2) =____

Question 2

$2 \frac{7}{8} + (1 \frac{3}{5} + 1 \frac{1}{8}) = 2 \frac{7}{8} + (1 \frac{24}{40} + 1 \frac{5}{40}) = 2 \frac{7}{8} + 2 \frac{29}{40} = 2 \frac{35}{40} + 2 \frac{29}{40} = 4 \frac{64}{40} = 5 \frac{3}{5 }$ _
$7 \frac{1}{2} - ( 1 \frac{3}{8} + 1 \frac{1}{2} ) = 7 \frac{1}{2} - ( 1 \frac{3}{8} + 1 \frac{4}{8} ) = 7 \frac{1}{2} - 2 \frac{7}{8} = 7 \frac{4}{8} - 2 \frac{7}{8} = 4 \frac{5}{8}$ _
$9 \frac{1}{16} - ( \frac{5}{8} + \frac{7}{16} ) = 9 \frac{1}{16} - (\frac{10}{16} + \frac{7}{16} ) = 9 \frac{1}{16} - 1 \frac{1}{16} = 8$ _
$7 \frac{3}{4} + ( 2\frac{7}{8} - 1 \frac{3}{4} ) =7 \frac{3}{4} + (2 \frac{7}{8} - 1 \frac{6}{8} ) = 7 \frac{3}{4} + 1 \frac{1}{8} = 7 \frac{6}{8} + 1 \frac{1}{8} = 8 \frac{7}{8}$ _
$3 \frac{7}{8} + (2 \frac{3}{5} - 1 \frac{5}{8} ) = 3 \frac{7}{8} + (2 \frac{24}{40} - 1 \frac{25}{40}) = 3 \frac{7}{8} + \frac{39}{40} = 3 \frac{35}{40} + \frac{39}{40} = 4 \frac{34}{40} = 4 \frac{17}{20}$ _
$3 \frac{7}{8} - (2 \frac{3}{8} - 1 \frac{3}{4} ) = 3 \frac{7}{8} - (2 \frac{3}{8} - 1 \frac{6}{8} ) = 3 \frac{7}{8} - \frac{5}{8} = 3 \frac{2}{8} = 3 \frac{1}{4}$ _
$5 \frac{1}{6} \times 4 + 2 \frac{5}{6} \times 4 + 8 \frac{1}{2} \times 4 = 20 \frac{2}{3} + 11 \frac{1}{3} + 34 = 66$ _
$3 \frac{1}{2} \times 2 + 2 \frac{1}{2} \times 2 + 3 \frac{1}{2} \times 2 = 7 + 5 + 7 = 19$ _
$3 \frac{1}{2} + (2 \frac{3}{4} + 1 \frac{1}{2} ) = 3 \frac{1}{2} + (2 \frac{3}{4} + 1 \frac{2}{4} ) = 3 \frac{1}{2} + 4 \frac{1}{4} = 3 \frac{2}{4} + 4 \frac{1}{4} = 7 \frac{3}{4}$

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