22.4 liters of HCL dissolved in 200 milliliters of H2O calculate the volume part of HCL

Question

22.4 liters of HCL dissolved in 200 milliliters of H2O calculate the volume part of HCL

Answer 1

N(HCl)=22.4/22.4=1mol'
m(HCl)=1mol'*36.5g mol'=36.5g
p(H20)=1g m3
m(H20)=200ml*1g m3=200g
w(HCl)=36,5/200=0,1825*100=18.25%