1/(2-x)-1=1/(x-2)-(6-x)/(3x²-12)
D(y):
2-x≠0, x≠2
x-2≠0, x≠2
3x²-12≠0, 3(x²-4)≠0, (x-2)(x+2)≠0, x≠-2, x≠2
→ x≠-2, x≠2
-1/(x-2)-1=1/(x-2)-(6-x)/3(x-2)(x+2) /*3(x-2)(x+2)
-1*3(x+2)-1*3(x-2)(x+2)=1*3(x+2)-(6-x)
-3x-6-3(x²-4)=3x+6-6+x
-3x-6-3x²+12=4x
3x²+7x-6=0
D=7²-4*3*(-6)=49+72=121
√D=11
x₁=(-7+11)/2*3=4/6=2/3
x₂=(-7-11)/2*3=-18/6=-3
Ответ: x₁=2/3, x₂=-3