А 2 +b2+ab и (a+b)2 при a=1 и b = 0,5

Question

А 2 +b2+ab и (a+b)2 при a=1 и b = 0,5

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Answer 1

a^2-b^2/2ab /(1/a-1/b) при a=4/3 и b=7/3 

 

a^2-b^2/2ab /(1/a-1/b) = ((a-b)(a+b))/2ab/(1/a-1/b) = ((a-b)(a+b))/2ab/((b-a)/ab) =

(-((b-a)(a+b))/2ab)(ab/(b-a)) = -(a+b)/2

 

-(4/3+7/3)/2 = -11/6

Answer 2

2+0,5•2+1•0,5=3,5
(1+0,5)2=1