Помогите срочно!!!!!!!!!!!!ОЧЕНЬ СРОЧНО

А) $\frac{1}{6} + \frac{1}{9} = \frac{3+2}{18}= \frac{5}{18}$
б) $\frac{2}{9} + \frac{5}{6} = \frac{4+15}{18} = \frac{19}{18} = 1 \frac{1}{18}$
в) $\frac{2}{9} + \frac{3}{8} = \frac{16+27}{72}= \frac{43}{72}$
г) $\frac{2}{10} + \frac{6}{15} = \frac{1}{5} + \frac{2}{5} = \frac{3}{5}$ — сократили обе дроби (первую на два, вторую на три)
д) $\frac{3}{10} + \frac{2}{12} = \frac{3}{10} + \frac{1}{6} = \frac{9+5}{30} = \frac{14}{30} = \frac{7}{15}$
е) $\frac{5}{12} + \frac{4}{15} = \frac{25+16}{60} = \frac{41}{60}$
ж) $\frac{3}{4} + \frac{5}{18} = \frac{21+10}{36} = \frac{31}{36}$
з) $\frac{2}{26} + \frac{3}{39} = \frac{1}{13} + \frac{1}{13} = \frac{2}{13}$
и) $\frac{7}{34} + \frac{5}{51} = \frac{42+20}{204} = \frac{62}{204} = \frac{31}{102}$
к) $\frac{4}{210} + \frac{5}{140} = \frac{8+15}{420} = \frac{23}{420}$
л) $\frac{7}{450} + \frac{8}{180} = \frac{14+40}{900} = \frac{54}{900} = \frac{3}{50}$
м) $\frac{9}{180} + \frac{7}{120} = \frac{3}{60} + \frac{7}{120} = \frac{6+7}{120} = \frac{13}{120}$