Решите неравенство пж: 1) 3x+7>13. 2) 5x-15>0. 3) 16-4x<0. 4) 6(x+1)>5x+3. Решите...

1) $3x+7\ \textgreater \ 13$
$3x\ \textgreater \ 6$
$x\ \textgreater \ \frac{6}{3}$
$x\ \textgreater \ 2$
2) $5x-15\ \textgreater \ 0$
$5x\ \textgreater \ 15$
$x\ \textgreater \ \frac{15}{5}$
$x\ \textgreater \ 3$
3) $16-4x\ \textless \ 0$
$4x\ \textgreater \ 16$
$x\ \textgreater \ \frac{16}{4}$
$x\ \textgreater \ 4$
4) $-3\ \textless \ 1+2x\ \textless \ 4$
$-4\ \textless \ 2x\ \textless \ 4$
$-2\ \textless \ x\ \textless \ 2$
5) $1\ \textless \ 3-x\ \textless \ 5$
$-2\ \textless \ -x\ \textless \ 2$
$2\ \textgreater \ x\ \textgreater \ -2$
В 4 и 5 неравенствах я не уверен
Надеюсь, помог