Помогите срочно в течении 15 мин

$1)3x^2+8x-3=0 \\ D= \sqrt{8^2-4*3*(-3)} = \sqrt{100} =10 \\ \\ x_1= \frac{-8+10}{6}= \frac{1}{3} \\ \\ x_2=\frac{-8-10}{6}=-3 \\ \\ \\ 2)4x^2+2x+1=0 \\ D= \sqrt{2^2-4*4*1} = \sqrt{-12}$
нет решения
$3) \frac{6}{x-2} + \frac{5}{x} =3 \\ \frac{6}{x-2} + \frac{5}{x}-3=0 \\ \\ \frac{6x+5(x-2)-3x(x-2)}{x(x-2)} = \frac{6x+5x-10-3x^2+6x}{x(x-2)} = 17x-10-3x^2=0 \\ \\ -3x^2+17x-10=0 \\ D= \sqrt{17^2-4*(-3)(-10)} = \sqrt{169} =б13 \\ \\ x_1= \frac{-17+13}{-6}= \frac{2}{3} \\ \\ x_2=\frac{-17-13}{-6}=5 \\ \\ \\ 4) \frac{x^2}{x^2-9} = \frac{12-x}{x^2-9} \\ \\ x^2=12-x \\ x^2+x-12=0 \\ D= \sqrt{1^2-4*1*(-12)} = \sqrt{49} =б7 \\ \\ x_1= \frac{-1+7}{2} =3 \\ \\ x_2 =\frac{-1-7}{2} =-4$
$5) \frac{5}{x-3} - \frac{8}{x} =3 \\ \frac{5}{x-3} - \frac{8}{x}-3=0 \\ \\ \frac{5x-8(x-3)-2x(x-3)}{x(x-3)} = \frac{5x-8x+24-3x^2+9x}{x(x-3)} =6x+24-3x^2=0 \\ \\ -3x^2+6x+24=0|:(-3) \\ x^2-3x-8=0 \\ D= \sqrt{(-2)^2-4*1*(-8)}= \sqrt{36}=б6 \\ \\ x_1= \frac{2+6}{2} =4 \\ \\ x_2= \frac{2-6}{2} =-2 \\ \\ \\ 6) \frac{8}{x-3} - \frac{10}{x} =2 \\ \frac{8}{x-3} - \frac{10}{x}-2=0 \\ \\ \frac{8x-10(x-3)-2x(x-3)}{x(x-3)} = \frac{8x-10x+30-2x^2+6x}{x(x-3)} =4x+30-2x^2=0 \\ \\ -2x^2+4x+30=0|:(-2) \\$
$x^2-2x-15=0 \\ D= \sqrt{(-2)^2-4*1*(-15)} = \sqrt{64} =б8 \\ \\ x_1= \frac{2+8}{2} =5 \\ \\ x_2=\frac{2-8}{2} =-3$