4x - y = 6 4x^2 + y^2 = 8-------------y = 4x - 6 4x^2 + ( 4x - 6 )^2 = 8 4x^2 + 16x^2 - 48x + 36 = 8 20x^2 - 48x + 28 = 0 4( 5x^2 - 12x + 7 ) = 0 D = 144 - 140 = 4 = 2^2 X1 = ( 12 + 2 ) : 10 = 1,4 X2 = ( 12 - 2 ) : 10 = 1y1 = 4•1,4 - 6 = 5,6 - 6 = - 0,4 y2 = 4•1 - 6 = - 2 Ответ ( 1,4 ; - 0,4 ) ; ( 1 ; - 2 )