Дано sin(a)= -/3 < a <3/2 Найти: cos(/6+a)

Question

Дано
sin(a)= -/3
< a <3<img src="https://tex.z-dn.net/?f=+%5Cpi+" id="TexFormula3" title=" \pi " alt=" \pi " align="absmiddle" class="latex-formula">/2
Найти:
cos(/6+a)

Answer 1

I hope this helps you

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