Помогите, заранее спасибо)

А)
$(x - \frac{1}{4} ) + 3 \frac{1}{12} = 7 \frac{1}{3} \\ \\ x - \frac{1}{4} + 3 \frac{1}{12} = 7 \frac{1}{3} \\ \\ x = 7 \frac{1}{3} - 3 \frac{1}{12} + \frac{1}{4} \\ \\ x = 7 \frac{4}{12} - 3 \frac{1}{12} + \frac{3}{12} \\ \\ x = 4 \frac{1}{2}$

б)
$6 \frac{2}{3} - (x + \frac{1}{4} ) = 2 \frac{1}{6} \\ \\ 6 \frac{2}{3} - x - \frac{1}{4} = 2 \frac{1}{6} \\ \\ - x = 2 \frac{1}{6} - 6 \frac{2}{3} + \frac{1}{4} \\ \\ x = - 2 \frac{2}{12} + 6 \frac{8}{12} - \frac{3}{12} \\ \\ x = 4 \frac{1}{4}$