РЕШИТЕ ПОЖАЛУЙСТА!1!1!1!

Решите задачу:

${64}^{4} + 9 {x}^{2} + 1 - 48 {x}^{3} + 16 {x}^{2} - 6x = 32 {x}^{2} - 12x + 1 \\ 64 {x}^{4} - 7 {x}^{2} - 48 {x}^{3} + 6x = 0 \\ x(64 {x}^{3} - 48 {x}^{2} - 7x + 6) = 0 \\ x(8 {x}^{2} (8x - 3) - 3x(8x - 3 ) - 2(8x - 3)) = 0 \\ x(8x - 3)(8x ^{2} - 3x - 2) = 0 \\ x = 0 \\ x = \frac{3}{8} \\ x = \frac{3 + \sqrt{73} }{16 } \\ x = \frac{3 - \sqrt{73} }{16}$