(p^2−p+4)⋅(12p^2+p−4)

Question

(p^2−p+4)⋅(12p^2+p−4)

Answer 1

(p^2-p+4)(12p^2+p-4)=12p^4+p^3-4p^2-12p^3-p^2+4p+48p^2+4p-16=12p^4-11p^3+43p^2+8p-16

Comments

Спасибооо