(х-3)(х-1)^3+(3-х)(х-2)^3=7(х-3)

Question

(х-3)(х-1)^3+(3-х)(х-2)^3=7(х-3)

Answer 1

(х-3)(х-1)^3+(3-х)(х-2)^3=7(х-3)корень x=3
делим на x-3
(x-1)^3-(x-2)^2=7
(x-1-(x-2))((x-1)^2+(x-1)(x-2)+(x-2)^2))=7
x2-2x+1+x2-x-2x+2+x2-4x+4=7
3x2-9x+7=7
3x(x-3)=0
x=0 x=3