Решите уравнения: 8x(1+2x)-(4x+3)(4x-3)=2 (8-9x)x=-40+(6-3x)(6+3x) (x-6)²-x(x+8)=2 16x(2-x)+(4x-5)²=1 9x²-1-(3x-2)²=0 (4x-3)(3+4x)-2x(8x-1)=0
1) (8+16х) - (16х^2-9) = 2 8х+16х^2-16х^2+9 = 2 8х = -7 х = -7/8 2) 8х-9х^2 = -40+(36-9х^2) -9х^2+9х^2+8х = -40+36 8х = -4 х= -1/2 3) (х^2-12х+36)-(х^2+8х) = 2 х^2-12х+36-х^2-8х = 2 -20х = 2-36 х = -34/-20
4) 32х-16х^2+(16х^2+40+25) = 1 32х-16х^2+16х^2+40+25 = 1 32х = 64 х = 2 5) 9х^2-1-(9х^2+12+4) = 0 9х^2-1-9х^2-12-4 = 0 -1-16 = 0 -17 = 0 6) 16х^2-9-16х^2+2х = 0 2х-9 = 0 х = 4,5