Помогите пожалуйста,2 выходит,мой последний шанс исправить! Моллюю

$- 9 * (- \frac{1}{3} ) ^{3} =-9*(- \frac{1}{27})= \frac{1}{3}$

c³ * c²² = c³⁺²² = c²⁵
c¹⁸ : c⁶ = c¹⁸⁻⁶ = c¹²
(c⁴)⁶ = c²⁴
(3c)⁵ = 3⁵ * c⁵ = 243c⁵

- 4x⁵y² * 3xy⁴ = - 12x⁵⁺¹y²⁺⁴ = - 12x⁶y⁶
(3x²y³)² = 9x⁴y⁶

$\frac{3y}{3xy} = \frac{1}{x} \\\\ \frac{9 y^{2} }{18xy}= \frac{y}{2x} \\\\ \frac{22p ^{4} q^{2} }{99 p^{5}q } = \frac{2q}{9p}\\\\\\ \frac{3 ^{6}*27 }{81 ^{2} }= \frac{3 ^{6} *3 ^{3} }{(3 ^{4}) ^{2} } = \frac{3 ^{9} }{3 ^{8} }=3$

$3 \frac{3}{7} x^{5} y^{6}*(-2 \frac{1}{3} x^{5}y) ^{2} = \frac{24}{7} x^{5} y^{6} * (\frac{7}{3} x^{5}y) ^{2} = \frac{24}{7} x^{5} y^{6} * \frac{49}{9} x^{10} y^{2} = \frac{56}{3} x^{15} y^{8}$ $18 \frac{2}{3} x^{15} y^{8} \\\\( a ^{n+1}) ^{2} :a ^{2n} =a ^{2n+2} :a ^{2n}=a ^{2n+2-2n} =a ^{2}$