1) tg2x= -^3 2) f(x)=x-2/x+3 Найти f '(x), f '(-2)

Question

1) tg2x= -^3
2) f(x)=x-2/x+3 Найти f '(x), f '(-2)

Answer 1

1)
tg2x=-arctg(3)+Пn
tgx=-arctg(3/2)+П/2n,n есть Z
2)f'(x)=(x-2)'(x+3)-(x-2)(x+3)'/(x+3)^2
(x+3)-(x-2)/(x+3)^2=x+3-x+2/(x+3)^2=5/(x+3)^2
f'(-2)=5/(-2+3)^2=5/1=5