найдите g' (x)=(π/18) если g (x)=1/3 ctg 3x

Question

найдите g' (x)=(π/18) если g (x)=1/3 ctg 3x

Answer 1

G'(x)=1/3 * (-1/sin^2 3x) * 3= -1/sin^2 3x
g' (π) = -1/sin^2 π/6 = -1/1/4 = -4