Решите уравнение (2x^2+15x-8)(-3x^2-7x+6)=0

$( {2x}^{2} + 15x - 8)( { - 3x}^{2} - 7x + 6) = 0 \\ {2x}^{2} + 15x - 8 = 0 \\ { - 3x}^{2} - 7x + 6 = 0 \\ d1 = {15}^{2} - 4 \times 2 \times ( - 8) = 225 + 64 = 289 \\ x1 = \frac{17 - 15}{4} = 0.5 \\ x2 = \frac{ - 15 - 17}{4} = - 8 \\ d2 = {( - 7)}^{2} - 4( - 3) \times 6 = 49 + 72 = 121 \\ x1 = \frac{11 + 7}{ - 3 \times 2} = - 3 \\ x2 = \frac{7 - 11}{ - 6} = \frac{4}{6} = \frac{2}{3} \\$

ответ:0,5;-8;-3;2/3