(2x - 7)^2 > (6x + 1 ) ^2

Question

(2x - 7)^2 > (6x + 1 ) ^2

Answer 1

(2x)^2-2×2×7+7^2>(6x)^2+1×6×1+1^2
4x^2-28+49>36x^2+12+1
4x^2-36x^2>12+1+28+49
-32x^2>-8
x^2<-8÷32<br>x^2>-0.25
x>0.5;-0.5