Решить систему уравнений 2/x+y/3=3 x/2+3/y=3/2

$\left \{ {{ \frac{2}{x}=a} \atop { \frac{y}{3} =b}} \right. \\ \left \{ {{a+b=3} \atop { \frac{1}{a}+ \frac{1}{b} = \frac{3}{2} }} \right. \\ \left \{ {{a+b=3} \atop { \frac{a+b}{ab} = \frac{3}{2} }} \right. \\ \left \{ {{a+b=3} \atop { ab = 2 }} \right. \\ \left \{ {{ \left \{ {{a=1} \atop {b=2}} \right. } \atop { \left \{ {{a=2} \atop {b=1}} \right.}} \right. \\ \left \{ {{ \left \{ {{x=2} \atop {y=6}} \right. } \atop { \left \{ {{x=1} \atop {y=3}} \right.}} \right. \\$
Ответ: (1;3) или (2;6)